---
title: "One-Shot Deformation"
source: https://www.jemoka.com/posts/kbhone_shot_deformation/
---

We have an expression:
\begin{equation} B = \frac{FL^{3}}{3EI} = \frac{N m^{3}}{3 p m^{4}} = \frac{Nm^{3}}{\frac{N}{m^{2}}m^{4}} = m \end{equation}
With constants:
\(B\): \(m\), deflection at the point of force application \(F\): \(N\), force applied \(L\): \(m\), distance between fixed point and point of force application \(E\): \(p=\frac{N}{m^{2}}\), elastic modulus \(I\): \(m^{4}\), second moment of area As per measured:
\(B\): \(9.15 \cdot 10^{-4} m\) \(F\): \(20N\) \(L\): \(9.373 \cdot 10^{-2} m\) \(I\): \(1.37 \cdot 10^{-10} m^{4}\) = \(\frac{WH^{3}}{12}\) = \(\frac{(6.25 \cdot 10^{-3})(6.4 \cdot 10^{-3})^{3}}{12}\) Theoretical:
\(E\): \(7 \cdot 10^{10} P\) As calculated:
\(B\): \(5.74 \cdot 10^{-4} m\)
