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@jemoka / Jemoka Knowledge Base / raw/concept/kbhlevel_set.md
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--- title: "level set" source: https://www.jemoka.com/posts/kbhlevel_set/ --- occasionally, you can’t really get a specific solution. \begin{equation} \dv{y}{t} = e^{t}\cos y \end{equation} after doing the , you get: \begin{equation} \ln (\sec y + \tan y) - e^{t} = C \end{equation} you get sets of this function \(F(t,y)\) which shifts it up and down, by any constant C. But at any given \((t,y)\), you get a slope \(e^{t}\cos y\).