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@jemoka / Jemoka Knowledge Base / wiki/concepts/1v_1.md
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--- title: "-1v=-v" type: concept related: [Additive Identity] source: https://www.jemoka.com/posts/kbh1v_1/ confidence: high status: active --- \begin{align} v+(-1)v &= (1+(-1))v \\ &= 0v \\ &= 0 \end{align} As \((-1)v=0\), \((-1)v\) is the additive identity of \(v\) which we defined as \(-v\) \(\blacksquare\).