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@jemoka / Jemoka Knowledge Base / wiki/concepts/log_laws.md
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--- title: "log laws" type: concept source: https://www.jemoka.com/posts/kbhlog_laws/ confidence: high status: active --- \begin{equation} \log a^{b} = b\log a \end{equation} \begin{equation} \log (ab) = \log a + \log b \end{equation} \begin{equation} \log (\frac{a}{b}) = \log a - \log b \end{equation}