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@jemoka / Jemoka Knowledge Base / wiki/concepts/newton_s_law_of_cooling.md
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--- title: "Newton's Law of Cooling" type: concept source: https://www.jemoka.com/posts/kbhnewton_s_law_of_cooling/ confidence: high status: active --- Putting something with a different temperature in a space with a constant temperature. The assumption underlying here is that the overall room temperature stays constant (i.e. the thing that’s cooling is so small that it doesn’t hurt room temperature). \begin{equation} y’(t) = -k(y-T_0) \end{equation} where, \(T_0\) is the initial temperature. The intuition of this modeling is that there is some \(T_0\), which as the temperature \(y\) of your object gets closer to t. The result we obtain Solving \begin{equation} \int \frac{\dd{y}}{y-T_0} = \int -k \dd{t} \end{equation} we can solve this: \begin{equation} \ln |y-T_0| = -kt+C \end{equation} which means we end up with: \begin{equation} |y-T_0| = e^{-kt+C} = e^{C}e^{-kt} \end{equation} So therefore: \begin{equation} y(t) = T_0 + C_1e^{-kt} \end{equation} to include both \(\pm\) cases. this tells us that cooling and heating is exponential. We will fit our initial conditions rom data to obtain \(C_1\).